Respuesta :
The answer is 1,250 W.
Solution:
To use the power rule P = VI, we need to know both the current I flowing through the resistor, and the voltage V across the resistor. But by substituting Ohm’s law I = V/R, we can also express the power rule equation P = VI as
P = R (V/R)^2 = R V^2 / R^2 = V^2 / R
We can now substitute the values for the resistance and voltage into the equation to get the power rating:
P=V^2 / R = (120)^2 / 11.5 = 1252.17 Watts ≈ 1250 Watts
Solution:
To use the power rule P = VI, we need to know both the current I flowing through the resistor, and the voltage V across the resistor. But by substituting Ohm’s law I = V/R, we can also express the power rule equation P = VI as
P = R (V/R)^2 = R V^2 / R^2 = V^2 / R
We can now substitute the values for the resistance and voltage into the equation to get the power rating:
P=V^2 / R = (120)^2 / 11.5 = 1252.17 Watts ≈ 1250 Watts