Two square pyramids have the same volume. For the first pyramid, the side length of the base is 16in., and the height is 28 in. The second pyramid has a height of 112 in. What is the side length of the base of the second pyramids?
The volume of the pyramid is: V = ((Ab) * (h)) / 3 Where, Ab: base area h: height Substituting values we have: First pyramid: V1 = ((16 * 16) * (28)) / 3 V1 = 2389.333333 in ^ 3 Second pyramid: 2389.333333 = (L ^ 2 * (112)) / 3 Clearing L we have: L = root ((2389.333333) * (3/112)) L = 8 in Answer: The side length of the base of the second pyramids is: L = 8 in
