Answer:
b = [tex]2x+\frac{1}{3}+\frac{1}{x}[/tex]
Step-by-step explanation:
The area of the parallelogram is represented by [tex]6x^{2} +x+3[/tex]
The height is [tex]3x[/tex]
The base of the parallelogram, b, can be found by dividing the area by the height.
So, 'b' can be found as [tex]\frac{6x^{2}+x+3 }{3x}[/tex]
In simplified form, we can write this as :
=> [tex]\frac{6x^{2} }{3x}+\frac{x}{3x}+ \frac{3}{3x}[/tex]
=> [tex]2x+\frac{1}{3}+\frac{1}{x}[/tex]
Hence, base or 'b' is [tex]2x+\frac{1}{3}+\frac{1}{x}[/tex]
