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The lengths of the sides of triangle XYZ are in terms of the variable m, where m ≥ 6.


Which is correct regarding the angles of the triangle?
mX < mZ < mY
mY < mZ < mX
mY < mX < mZ
mZ < mY < mX


I think its c but im not sure

The lengths of the sides of triangle XYZ are in terms of the variable m where m 6Which is correct regarding the angles of the triangle mX lt mZ lt mY mY lt mZ l class=

Respuesta :

Answer:

mY < mZ < mX  

Step-by-step explanation:

Since we know that m≥6, we will substitute 6 in for m.

This makes XZ = m-3 = 6-3 = 3.  XY = m+8 = 6+8 = 14.  YZ = 2(6)+3 = 12+3 = 15.

This makes the sides, in order from least to greatest, XZ < XY < YZ.

The angles associated with these are opposite their corresponding sides; XZ corresponds with Y; XY corresponds with Z; and YZ corresponds with X.  This means our inequality would be

Y < Z < X

JeanaShupp

Answer: mY < mZ < mX  

Step-by-step explanation:

Given: The lengths of the sides of triangle XYZ are in terms of the variable m, where m ≥ 6.

Let m =6 the least value for m , then

[tex]XZ=m-3=6-3=3[/tex]

[tex]XY=m+8=6+8=14[/tex]

[tex]ZY= 2m+3=2(6)+3=12+3=15[/tex]

We can see [tex]XZ<XY<ZY[/tex]

Since the angle apposite to the larger side of a triangle is larger.

Therefore, mY < mZ < mX  

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