[tex]LINEAR \: \: EQUATIONS \\ \\ \\ Given \: expression \: \: - \: \\ \\ \frac{7}{3} (2x + 3) + \frac{3}{4} ( \frac{x}{5} - \frac{15}{2} ) = \frac{11}{8} \\ \\ \frac{14x}{3} + \frac{21}{3} + \frac{3x}{20} - \frac{45}{8} = \frac{11}{8} \\ \\ \frac{14x}{3} + \frac{3x}{20} + \frac{21}{3} - \frac{45}{8} = \frac{11}{8} \\ \\ \frac{289x}{60} = \frac{11}{8} + \frac{45}{8} - \frac{21}{3} \\ \\ \frac{289x}{60} = \frac{56}{8} - \frac{21}{3} \\ \\ \frac{289x}{60} = 7 - 7 = 0 \\ \\ \frac{289x}{60} = 0 \\ \\ \\ \: \: \: \:|| \: \: \: x = 0 \: \: \:|| \: \: \: \: \: \: \: \: \: \: \: \: \: Ans.[/tex]
