so line b is (0,0) and (4, -3/2)
slope = m = y2-y1/ x2-x1
= -3/2 - 0 / (4-0 )= -3/8
now using point slope y-y1=m(x-x1)
m=-3/8 and point is (0,0) to make it easier
y-0 = -3/8 (x-0)
y=-3/8x
so we have the first line done, now another line is parallel to line b which means they have the same slope
line 2 has slope = m = -3/8
and point (0,-7)
using point slope again y-y1=m(x-x1)
y- (-7) = (-3/8) (x-0)
y=(-3/8)x -7
hope that helps and is right
