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A circuit consists of a 9.0 v battery connected to three resistors (52 , 17 , and 140 ) in series. (a) find the current that flows through the battery.

Respuesta :

A) TOTAL Resistance = 41+18+120 = 179 ohms 
Current = V/R = 9 / 179 = 0.0503 A = 50.3 mA 

B) V = I*R = .0503 * 41 = 2.06 V 

C) V = I*R = .0503 * 18 = 0.91 V 

D) V = I*R = .0503 * 120 = 6.03 V

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