we are given
Event-A:
they are randomly handed either a blue, yellow, green, or red card
so, total number of cards =3
probability of selecting green cards = (number of green card)/(total number of cards)
probability of selecting green cards is [tex] \frac{1}{3} [/tex]
Let's assume
[tex] p(A)=\frac{1}{3} [/tex]
Event-B:
there are 8 boys and 12 girls in the class
total number of students =8+12=20
number of boys =8
probability of a boy = (number of boys)/(total number of students)
[tex] p(B)=\frac{8}{20} [/tex]
Since, events A and B are independent
so,
probability that the student chosen by Mr. Jackson will be a boy with a green card = p(A)*p(B)
probability that the student chosen by Mr. Jackson will be a boy with a green card = [tex] \frac{8}{20} *\frac{1}{3} [/tex]
[tex] =\frac{8}{20} *\frac{1}{3} [/tex]
[tex] =\frac{2}{15} [/tex]
probability that the student chosen by Mr. Jackson will be a boy with a green card is [tex] \frac{2}{15} [/tex]...........Answer
