Respuesta :
The dominant mode way of inheritance ratio is 12:3:1
12/16 = 0.75 = 75% = 801 or we can say phenotype :honey-nut and genotype:HHMM, HhMM,HHMm, HhMm,Hhmm
3/16 = 0.1875 = 18.75% = 200 or
phenotype: multigrain and genotype: hhMM, hhMm
So if we can say that 75% is 801, what about 100%
75% = 801
100%=?
100×801/75=1068
(1/16) ×1068 = 67 which is expected but observed is 55 for example
honey nut the observed is 801 and expected is 801.
multigrain the observed is 200 and the expected 200.
plain the observed is 55 and the expected is 67
12/16 = 0.75 = 75% = 801 or we can say phenotype :honey-nut and genotype:HHMM, HhMM,HHMm, HhMm,Hhmm
3/16 = 0.1875 = 18.75% = 200 or
phenotype: multigrain and genotype: hhMM, hhMm
So if we can say that 75% is 801, what about 100%
75% = 801
100%=?
100×801/75=1068
(1/16) ×1068 = 67 which is expected but observed is 55 for example
honey nut the observed is 801 and expected is 801.
multigrain the observed is 200 and the expected 200.
plain the observed is 55 and the expected is 67
Answer:
Honey Nut: with alleles H (dominant) h (recessive)
Multi-Grain: with alleles M (dominant) m (recessive)
HHMM Bear and a hhmm bear cross, and the F1s like honey nut. A cross of two F1 bears will produce the following sums two-locus genotype counts:
All F2 Bears with at least one H allele: 801
All F2 Bears with at least one M allele: 200
55 is the number of bears that is consistent with a dominant mode of inheritance at the 1% level of significance.
