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A pizza parlor offers pizzas with diameters of 8 in, 10 in, and 12 in. find the area of each size pizza. round to the nearest tenth. if the pizzas cost $9, $12, and $18 respectively, which is the better buy

Respuesta :

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Area od pizza, A = Pi*Diameter^2/4

A1 = Pi*8^2/4 = 50.27 in^2
A2 = Pi*10^2/4 = 78.54 in^2
A3 = Pi*12^2/4 = 113.10 in^2

Cost (C) per sq. in;
C1 = 50.27/9 = $5.59
C2 = 78.54/12 = $6.55
C3 = 113.10/18 = $6.28

The best buy is the first pizza with 8 in diameter as it costs the least per sq. inch.

Answer:

Area of Pizza 1 = 50.24 sq. inch, Area of Pizza 2 = 78.5 sq. inch, Area of Pizza 3 = = 113.04 sq. inch

Thus, the pizza with diameter 8 inch is better to buy.

Step-by-step explanation:

We are given three pizzas with three different diameters.

[tex]diametre_1[/tex] = 8 inch ⇒ [tex]radius_1[/tex] = 4 inch

[tex]diametre_2[/tex] = 10 inch ⇒ [tex]radius_1[/tex] = 5 inch

[tex]diametre_3[/tex] = 12 inch ⇒ [tex]radius_1[/tex] = 6 inch

Area of Circle = πr², where r is the radius of circle.

Area of Pizza 1 = 3.14 × 4 × 4 = 50.24 sq. inch

Area of Pizza 2 = 3.14 × 5 × 5 = 78.5 sq. inch

Area of Pizza 3 = 3.14 × 6 × 6 = 113.04 sq. inch

We are also given cost for each pizza.

[tex]Cost_1[/tex] = $9

[tex]Cost_2[/tex] = $12

[tex]Cost_3[/tex] = $18

To choose which one is a better pizza to buy, we calculate cost per square inch.

Cost per sq. inch = [tex]\frac{\text{Cost of Pizza}}{\text{Area of Pizza}}[/tex]

Pizza 1 = [tex]\frac{9}{50.24}[/tex] = 0.18$ per sq. inch

Pizza 2 = [tex]\frac{12}{78.5}[/tex] =  0.15$ per sq. inch

Pizza 1 = [tex]\frac{18}{113.04}[/tex] =  0.16$ per sq. inch

Thus, the pizza with diameter 10 inch is better to buy.

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