The wavelength of light visible to the human eye is on the order of 5 × 10−7 m. find the frequency of the lightwave if the speed of light in air is 2.99792 × 108 m/s. answer in units of s−1 .

Respuesta :

The relationship between speed, frequency and wavelength of an electromagnetic wave is
[tex]f= \frac{c}{\lambda} [/tex]
where
c is the speed of light
f is the frequency
[tex]\lambda[/tex] is the wavelength

the light wave in our problem has a wavelength of [tex]\lambda=5 \cdot 10^{-7}m[/tex], so we can use the previous equation to find its frequency
[tex]f= \frac{c}{\lambda}= \frac{2.99792 \cdot 10^8 m/s}{5 \cdot 10^{-7}m} = 6.0 \cdot 10^{14} Hz[/tex]

The frequency of the lightwave will be given as  [tex]6\times 10^{14}[/tex] Hz

What will be the frequency of the lightwave?

It is given that

The wavelength [tex]\lambda =5\times 10^{-7}[/tex]

The speed  [tex]C=2.99792\times 10^8 \ \frac{m}{s}[/tex]

The formula to find out the speed of the electromagnetic wave will be given by

[tex]f=\dfrac{C}{\lambda}[/tex]

here

c is the speed of light

f is the frequency

[tex]\lambda[/tex]  is the wavelength

Now to find the frequency put the values in the formula

[tex]f=\dfrac{2.99792\times 10^8}{5\times 10^{-7}}[/tex]

[tex]f=6\times 10^{14} \ Hz[/tex]

Thus the frequency of the lightwave will be given as  [tex]6\times 10^{14}[/tex] Hz

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