Respuesta :
L: length defective, T : texture defective.
Given that the strip is length defective, the probability that this strip is texture defective is given by
P (TL) =P (T ∩ L)=0.008= 0.08.P (L)0.1| www.imali.infoIf a strip is selected randomly from the process, and a quick measurement identifies it as failing the length test, the probability that a texture is defective is 8%
Represent the event that a strip fails the texture test with T, and the event that a strip fails the length test with L
So, we have:
[tex]\mathbf{P(T) = 5\%}[/tex]
[tex]\mathbf{P(L) = 10\%}[/tex]
[tex]\mathbf{P(T\ and\ L) = 0.8\%}[/tex]
The probability that a strip is defective given that it fails the length test is represented as: P(T|L)
So, we have:
[tex]\mathbf{P(T|L) = \frac{P(T\ and\ L)}{P(L)}}[/tex]
Substitute known values
[tex]\mathbf{P(T|L) = \frac{0.8\%}{10\%}}[/tex]
Cancel out the percentages
[tex]\mathbf{P(T|L) = \frac{0.8}{10}}[/tex]
Divide
[tex]\mathbf{P(T|L) = 0.08}[/tex]
Express as percentage
[tex]\mathbf{P(T|L) = 8\%}[/tex]
Hence, the probability that a texture is defective is 8%
Read more about probabilities at:
https://brainly.com/question/11234923