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A piece of metal ore weighs 8.25 g. when a student places it into a graduated cylinder containing water, the liquid level rises from 21.25 ml to 26.47 ml. what is the density of the ore? 0.312 g/ml 1.58 g/ml 3.21 g/ml 0.633 g/ml

Respuesta :

haneylia
26.47 mL - 21.25 mL = 5.22 mL

8.25 g / 5.22 mL = 1.58 g/mL

Density is defined as the ratio of mass is to volume, such that the higher the density of the substance higher will be its mass. It is expressed in the gram-centimeter³.

The density of the metal ore is 1.77 g/mL.

Given that,

  • Weight of metal ore = 9.25 g
  • Volume in the cylinder before metal ore = 21.25 mL
  • Volume rised in the cylinder after metal ore = 26.47 mL
  • Volume change = 26.47 - 21.25 = 5.22 mL

Now, from the formula of density,

[tex]\text{density} &=\dfrac{\text{mass}}{\text{volume}} \\\\\text{density} &=\dfrac{9.25 \;\text g}{5.22\;\text{mL}}[/tex]

density = 1.77 g/mL

Therefore, the density of the metal ore is 1.77 g/mL.

To know more about density, refer to the following link:

https://brainly.com/question/4284750

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