Respuesta :
Answer: 5.36 hours
Explanation:
[tex]Q=I\times t[/tex]
where Q= quantity of electricity in coloumbs
I = current in amperes = 50A
t= time in seconds = ?
[tex]Cu^{2+}+2e^{-1}\rightarrow Cu[/tex]
[tex]96500\times 2=193000Coloumb[/tex] of electricity deposits 1 mole of Cu.
1 mole of Copper is produced by = 193000 Coloumb
5 moles of Copper is produced by=[tex]\frac{193000}{1}\times 5=965000C[/tex]
[tex]965000=50\times t[/tex]
[tex]t=19300s[/tex] (1 hour=3600sec)
[tex]t=5.36hours[/tex]
An electrolytic is a type of electrochemical cell that utilises current or the energy source for the potential development across the cell in which the redox chemical reaction occurs.
For 5.36 hours constant current should be passed.
What is the relationship between the current and time?
Given,
Current (I)= 50A
Quantity of electricity (Q) is given as,
[tex]\rm Q = I \times t[/tex]
The half cell of the reaction can be shown as,
[tex]\rm Cu^{2+} + 2e^{-1} \rightarrow Cu[/tex]
1 mole of copper is deposited by,
[tex]96500 \times 2 = 193000 \;\rm coloumbs[/tex]
If,
1 mole of Copper = 193000 Coloumb
5 moles of Copper = X
Solving for X:
[tex]\begin{aligned}\rm X &= \dfrac{193000}{1}\times 5\\\\&= 965000 \;\rm C\end{aligned}[/tex]
Substituting values of Q and I in the above equation:
[tex]\begin{aligned}965000 &= 50 \times \;\rm t\\\\\rm t &= 19300 \;\rm sec\end{aligned}[/tex]
We know,
1 hour = 3600 sec
t = 5.36 hours.
Therefore, 5.36 hours are needed for a constant current supply.
Learn more about current and time here:
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