Answer:
No, the given circle is not passes through the point (5, 6).
Step-by-step explanation:
The given equation is
[tex](x-2)^2+(y-6)^2=4[/tex]
If the circle passes through a point, then the equation of circle must be satisfied by that point.
Check the given equation by the point (5,6).
Substitute x=5 and y=6 in the given equation.
[tex](5-2)^2+(6-6)^2=4[/tex]
[tex](3)^2+(0)^2=4[/tex]
[tex]9=4[/tex]
This statement is not true, because 9≠4.
The given circle is not passes through the point (5, 6).
