Respuesta :

Hello!

You put the numbers 1 to 6 in for n

= [tex]1^{2+1}= 1 [/tex]
=[tex]2^{2+1}= 8[/tex]
=[tex]3^{2+1}= 27[/tex]
=[tex]4^{2+1}= 64[/tex]
=[tex]5^{2+1}= 125[/tex]
=[tex]6^{2+1}= 216[/tex]

The first 6 numbers are 1, 8, 27, 64, 125, 216

Hope this helps!
pol0n
[tex]a_n=n^2+1 \\ \\ a_1=1^2+1=1+1=2 \\ a_2=2^2+1=4+1=5 \\ a_3=3^2+1=9+1=10 \\ a_4=4^2+1=16+1=17 \\ a_5=5^2+1=25+1=26 \\ a_6=6^2+1=36+1=37[/tex]

or:

[tex]a_n=n^{2+1} \\ a_1= 1^{2+1} =1^3=1 \\ a_2=2^{2+1}=2^3=8 \\ a_3=3^{2+1} =3^3=27 \\ a_4=4^{2+1} =4^3=64 \\ a_5=5^{2+1} =5^3=125 \\ a_6=6^{2+1} =6^3=216[/tex]