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A company that manufactures golf balls is looking for golfers that can hit a golf ball at least 300 yards. suppose the probability that a golfer at a local golf course can hit the ball at least 300 yards is 0.35. if six golfers are selected at random, what is the probability that at least four of them can hit the ball at least 300 yards?

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Robinson555
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The probability that at least four of them can hit the ball at least 300 yards is 0.117.

What is the probability?

Probability refers to a possibility that deals with the occurrence of random events.

The probability of all the events occurring need to be 1.

The probability of hitting the ball, P( hit) = 0.35

The probability of not hitting the ball, P( not hit) = 0.65

Using probability distribution theorem;

[tex]P(4 hit) = \: ^nC_xp^x(1-p)^{n-x}[/tex]

Here n = 6 , x = 4

[tex]P(4 hit) = \: ^6C_4(0.35)^4(1-0.35)^{6-4}\\\\P(4 hit) = \: ^6C_4(0.35)^4(0.65)^{2}\\\\P(4 hit) = \: 15(0.35)^4(0.65)^{2}[/tex]

[tex]P(5hit) = \: ^6C_5(0.35)^5(0.65)^{1}\\\\P(5hit) = \: 6(0.35)^5(0.65)[/tex]

[tex]P(6 hit) = \: ^6C_6(0.35)^6(0.65)^{0}\\\\P(6 hit) = \: (0.35)^6[/tex]

The probability that at least four of them can hit the ball at least 300 yards is 0.117.

Learn more about probability here;

https://brainly.com/question/11234923

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