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A sample of an unknown substance has a mass of 0.158 kg. If 2,510.0 J of heat is required to heat the substance from 32.0°C to 61.0°C, what is the specific heat of the substance? Use mc029-1.jpg.

Respuesta :

kenmyna

The specific  heat of the substance  is  0.548  J/g/c


calculation

 Specific heat is calculated  using  Q=MCΔT  formula, where;

Q(heat)=  2510.0 j

 M (mass)=  0.158  kg  convert into  g

   = 1 Kg = 1000 g

     0.158 kg= ? g

      = (0.158 kg  x  1000g)  / 1  kg = 158  g

C(  specific heat capacity) = ?

ΔT(change in temperature)  = 61.0 -32c   = 29 c


   make  C  the subject of the  formula  by dividing both side by m andΔT

  c=  Q /mΔT

 C=  [2510.0 j  /    158 g x 29]  = 0.548  j/g/c



samueladesida43

The specific heat capacity of the unknown substance that has a mass of 0.158 kg is 547.8 J/kg°C.

HOW TO CALCULATE SPECIFIC HEAT CAPACITY:

The specific heat capacity of a substance can be calculated using the following formula:

Q = m × c × ∆T

Where;

  • Q = quantity of heat absorbed (J)
  • c = specific heat capacity (4.18 J/g°C)
  • m = mass of substance
  • ∆T = change in temperature (°C)

According to this question, 2,510.0 J of heat is required to heat the 0.158kg substance from 32.0°C to 61.0°C. The specific heat capacity can be calculated:

2510 = 0.158 × c × (61°C - 32°C)

2510 = 4.582c

c = 2510 ÷ 4.582

c = 547.8 J/kg°C

Therefore, the specific heat capacity of the unknown substance that has a mass of 0.158 kg is 547.8 J/kg°C.

Learn more about specific heat capacity at: https://brainly.com/question/2530523?referrer=searchResults

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