There are 7 green aprons and they are to be assigned randomly to twenty five volunteers. Therefore, the probability of being assigned a green apron is:
[tex] P(G)=\frac{7}{25} [/tex]
Thus, the the probability that a volunteer is assigned an apron that is NOT green is a complementary event and is thus given by:
[tex] P(G^c)=1-P(G)=1-\frac{7}{25} [/tex]
[tex] P(G^c)=\frac{18}{25}=0.72 [/tex]
Therefore, in terms of percentage, the odds of not getting a green apron is 72%.
The probability that a volunteer is assigned an apron that is NOT green is 0.72 or 72%.
Twenty-five volunteers will wear one of 6 blue, 7 green, 8 yellow, and 4 red aprons during an upcoming food drive.
If the aprons are assigned randomly, what is the probability that a volunteer is assigned an apron that is NOT green?
Total number of volunteers = 25
Total number of green volunteers = 7
Therefore,
The probability of choosing green volunteers is,
[tex]\rm P(green) = \dfrac{Number \ of \ green \ volunteers}{Total \ number \ of \ volunteers}\\ \\ p(green ) = \dfrac{7}{25}[/tex]
Therefore,
The probability that a volunteer is assigned an apron that is NOT green is a complimentary event and is thus given by:
[tex]\rm p(not \ green) = 1- p(green)\\ \\ p(not \ green) = 1- \dfrac{7}{25}\\ \\ p(not \ green) = \dfrac{25-7}{25}\\ \\p(not \ green) = \dfrac{18}{25}\\ \\ p(not \ green) = 0.72[/tex]
Hence, The probability that a volunteer is assigned an apron that is NOT green is 0.72 or 72%.
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