Respuesta :
Number of Hours Amount of Gas
Spent Driving Left in Tank,
(h) in gallons (g)
h1=3 g1=12
h2=5 g2=8
h3=7 g3=4
h4=9 g4=0
h2-h1=5-3=2 g2-g1=8-12=-4
h3-h2=7-5=2 g3-g2=4-8=-4
h4-h3=9-7=2 g4-g3=0-4=-4
The equation that models the amount of gas left in the car as phan drives is a linear equation:
g-g1=m(h-h1)
Amount of gas left in the car: g
Number of hours spent driving: h
m=(g2-g1)/(h2-h1)
m=(8-12)/(5-3)
m=(-4)/(2)
m=-2
g-g1=m(h-h1)
g-12=(-2)(h-3)
g-12=(-2)(h)+(-2)(-3)
g-12=-2h+6
g-12+12=-2h+6+12
g=-2h+18
Answer: The equation models the amount of gas left in the car as Phan drives is: g=-2h+18
How many gallons of gasoline does it take to fill her tank?
This is when h=0
h=0→g=-2(0)+18→g=-0+18→g=18
Answer: It takes 18 gallons of gasoline to fill her tank
Spent Driving Left in Tank,
(h) in gallons (g)
h1=3 g1=12
h2=5 g2=8
h3=7 g3=4
h4=9 g4=0
h2-h1=5-3=2 g2-g1=8-12=-4
h3-h2=7-5=2 g3-g2=4-8=-4
h4-h3=9-7=2 g4-g3=0-4=-4
The equation that models the amount of gas left in the car as phan drives is a linear equation:
g-g1=m(h-h1)
Amount of gas left in the car: g
Number of hours spent driving: h
m=(g2-g1)/(h2-h1)
m=(8-12)/(5-3)
m=(-4)/(2)
m=-2
g-g1=m(h-h1)
g-12=(-2)(h-3)
g-12=(-2)(h)+(-2)(-3)
g-12=-2h+6
g-12+12=-2h+6+12
g=-2h+18
Answer: The equation models the amount of gas left in the car as Phan drives is: g=-2h+18
How many gallons of gasoline does it take to fill her tank?
This is when h=0
h=0→g=-2(0)+18→g=-0+18→g=18
Answer: It takes 18 gallons of gasoline to fill her tank
Answer:
A on Edg
Step-by-step explanation:
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