It is given that half the squares on a checkerboard are black. Therefore, the other half will be red. Thus, the probability of finding a red square on the checkerboard is: [tex] P(red)=\frac{1}{2} [/tex]
Now, the Probability of a die landing with a value of 2 is:
[tex] P(2)=\frac{1}{6} [/tex]
Therefore, the probability of the event that the die face is a 2 and lands on the red square is:
[tex] P(red)\times P(2)=\frac{1}{2}\times \frac{1}{6} =\frac{1}{12} [/tex]
This can be expressed as percentage as: [tex] \frac{1}{12}\times 100\approx 8.33 [/tex]%
