Answer:
[tex]\Sin B = \frac{3}{5}[/tex]
Step-by-step explanation:
Applying the Pythagorean theorem in the triangle ABC, we have
[tex]AC=\sqrt{AB^2-BC^2}\\\\AC=\sqrt{20^2-16^2}\\\\AC=\sqrt{400-256}\\\\AC=\sqrt{144}\\AC=12[/tex]
Now, we can apply the formula for sine function
[tex]\sin B = \frac{AC}{AB}[/tex]
Plugging the known values, we get
[tex]\sin B = \frac{12}{20}[/tex]
On simplifying this fraction, we get
[tex]\sin B = \frac{3}{5}[/tex]
