Respuesta :
Answer: The mass of ammonia produced is 28.22 g
Explanation:
To calculate the number of moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex] .....(1)
- For hydrogen gas:
Given mass of hydrogen gas = 10.0 g
Molar mass of hydrogen gas = 2 g/mol
Putting values in equation 1, we get:
[tex]\text{Moles of hydrogen gas}=\frac{10.0g}{2g/mol}=5mol[/tex]
- For nitrogen gas:
Given mass of nitrogen gas = 80.0 g
Molar mass of nitrogen gas = 28 g/mol
Putting values in equation 1, we get:
[tex]\text{Moles of nitrogen gas}=\frac{80.0g}{28g/mol}=2.86mol[/tex]
The given chemical equation follows:
[tex]N_2+3H_2\rightarrow 2NH_3[/tex]
By Stoichiometry of the reaction:
3 moles of hydrogen gas reacts with 1 mole of nitrogen gas
So, 5 moles of hydrogen gas will react with = [tex]\frac{1}{3}\times 5=1.66mol[/tex] of nitrogen gas
As, given amount of nitrogen gas is more than the required amount. So, it is considered as an excess reagent.
Thus, hydrogen gas is considered as a limiting reagent because it limits the formation of product.
By Stoichiometry of the reaction:
3 moles of hydrogen gas produces 1 mole of ammonia
So, 5 moles of hydrogen gas will produce = [tex]\frac{1}{3}\times 5=1.66moles[/tex] of ammonia
Now, calculating the mass of ammonia from equation 1, we get:
Molar mass of ammonia = 17 g/mol
Moles of ammonia = 1.66 moles
Putting values in equation 1, we get:
[tex]1.66mol=\frac{\text{Mass of ammonia}}{17g/mol}\\\\\text{Mass of ammonia}=(1.66mol\times 17g/mol)=28.22g[/tex]
Hence, the mass of ammonia produced is 28.22 g
