cw916
contestada

Solve (x + 1 < 5) ∩ (x - 4 > -3).

{all real numbers}
{x | 1 < x < 4}
{x | x < 4 or x > 1}

Respuesta :

[tex](x + 1 \ \textless \ 5)\,\cap\,(x - 4 \ \textgreater \ -3)\\\\(x\ \textless \ 5-1)\,\cap\,(x\ \textgreater \ -3+4)\\\\(x\ \textless \ 4)\,\cap\,(x\ \textgreater \ 1)\\\\(-\infty;4)\,\cap\,(1;\infty)\\\\(1;4)\\\\\\\boxed{\{x\,|\,1\ \textless \ x\ \textless \ 4\}} [/tex]
pegisy

Answer:

{ x | 1 < x < 4}

Step-by-step explanation: