need help on solving problems with common tangents

First of all, tangents make an angle of 90 degrees with the radius of a circle.
Hence, Both the triangles are right angled.
Now apply pythagorean theorem on triangle LKJ, and find the length of tangent,
which is x= tan(68) * 3 = 7.42
Now, on LMJ to find MJ
so, MJ = 7.42 * tan(61) = 13.39
Hope it helps
The length of radius MJ exists at 5.99 units.
Given:
JL is a common tangent to circles M and K at point J.
If angle MLK measures 619.
Calculating the length JL utilizing the following tangent ratio.
tan(68°) = JL/3
Simplifying the above equation, we get
JL = 3 [tex]*[/tex] tan(68°)
JL = 7.4
From the figure, the measure of angle MLJ exists:
∠MLJ = MLK - JLK
Where:
∠JLK = 90° - 68° = 22°
We have:
∠MLJ = 61° - 22°
∠MLJ = 39°
The radius MJ exists then estimated utilizing the following tangent ratio
tan(39) = MJ/JL
tan(39) = MJ/7.4
Simplifying the above equation,
[tex]MJ = 7.4 * tan(39)[/tex]
Evaluating,
MJ = 5.99
Hence, the length of radius MJ exists at 5.99 units.
To learn more about calculating the radius
https://brainly.com/question/23025496
#SPJ2