First we have to calculate the time taken to travel the distance 30 m, is
[tex]t = \frac{distance}{velocity} = \frac{30 \ m}{10 \ m/s } = 3 \ s[/tex].
Now from equation of motion,
[tex]v = u + at[/tex]
Given, [tex]v = 10 \ m/s[/tex] .
As object starts from rest, so u = 0.
Substituting these values in above equation, we get
[tex]10 \ m/s = 0 + a \times 3 \ s \\\\ a = \frac{10}{3} = 3.33 \ m/s^2[/tex].
Thus, the acceleration is [tex]3.33 \ m/s^2[/tex]
