Vanadium (v) oxide reacts with calcium according to the chemical equation below. when 10.0 mole of v2o5 are mixed with 10.0 mole of ca, which is the limiting reagent?

Respuesta :

The limiting agent has due to following properties:

I. It completely reacted in the reaction.

II. It determines the amount of the product in mole.

The general reaction between Vanadium (v) oxide and Ca is as follows:

V2O5(s) + 5Ca(l) = 2V(l) + 5CaO(s)

Given that  mole of V2O5(s) =  10.0 mole

Mole of Ca= 10.0 mole

10.0 mole Ca  * 1 mole V2O5/ 5 mole Ca

= 2 mole V2O5

Hence used V2O5 is 2 mole , and Ca is completely used . thus here Ca is limiting agent and V2O5 is present in excess (10-2= 8 mole )