Answer:
[tex]\sqrt{4}\cdot \sqrt{15}=2\sqrt{15}[/tex]
Step-by-step explanation:
We have been given a radical expression [tex]\sqrt{60}[/tex]. We are asked to rewrite the given radicand as two factors, one of which is a perfect square.
We can rewrite 60 as product of 4 and 15 as:
[tex]\sqrt{4*15}[/tex]
Using property [tex]\sqrt{m} \cdot \sqrt{n} =\sqrt{m\cdot n}[/tex] we will get,
[tex]\sqrt{4}\cdot \sqrt{15}[/tex]
Since 4 is a perfect square, so we can simplify our expression as:
[tex]2\cdot \sqrt{15}[/tex].
