A solution of ammonia and water contains 3.80•10^25 molecules of water and 5.50•10^24 molecules of ammonia. How many hydrogen atoms are in this solution?

1 molecule of water=1 oxygen and 2 hydrogen
1 molecule of ammonia= 1 nitrogen and 3 hydrogen

Please show work

Respuesta :

N H in H2O = 3.80×10²⁵ ×[tex]\frac{2H}{1H2O}[/tex] = 7.60×10²⁵atoms of H

N H in NH3 = 5.50×10²⁴×[tex]\frac{3H}{1NH3}[/tex] = 1.65×10²⁵atoms of H

1.65×10²⁵+7.60×10²⁵= 9.25×10²⁵atoms of H