Answer: [tex]=1-(0.8)^{200}[/tex]
Step-by-step explanation:
Given: The probability of brake pads that come off the production line are considered defective. = 0.2
Therefore, the probability that the brake pads are not defective=1-0.2=0.8
The probability that all 200 pads are not defective P(all 200 non defective)=[tex](0.8)^{200}[/tex]
Then the probability that at least one brake pad is defective in an order of 200 pads
P(at least one defective)=1-P(all 200 non defective)
[tex]=1-(0.8)^{200}[/tex]
