Answer:
[tex]\text{The area of figure is }231 in^2[/tex]
Step-by-step explanation:
Given the figure we have to find the area of given figure
The figure consist of a parallelogram, a rectangle and a triangle
Base of parallelogram= GE=9 inches
Height of parallelogram=HF=11 inches
[tex]\text{Area of parallelogram is }base\times height[/tex]
[tex]=GE\times HF=9\times 11=99 in^2[/tex]
Length of rectangle=11 in.
Breadth of rectangle=9 in.
[tex]\text{Area of rectangle=}length \times breadth=11\times 9=99 in^2[/tex]
base of triangle=AB=6 in.
Height=HB=11 in.
[tex]\text{Area of triangle=}\frac{1}{2}\times base\times height[/tex]
[tex]=\frac{1}{2}\times 6\times 11=33 in^2[/tex]
Total area of figure is
[tex]ar(ABH)+ar(BCDH)+ar(HDEG)[/tex]
[tex]=99+99+33=231 in^2[/tex]
Option 2 is correct.
