For this case we have that by definition, the lateral area of a cylinder is given by:
[tex]A_ {l} = 2 * \pi * r * h[/tex]
Where:
A: It is the radius of the cylinder
h: It's the height
[tex]r = 4 \ units\\h = 6 \ units[/tex]
Substituting we have:
[tex]A_ {l} = 2 * \pi * 4 * 6\\A_ {l} = 48 \pi \ units ^ 2[/tex]
Answer:
[tex]48 \pi \ units ^ 2[/tex]
Option B
