What is the amplitude and period of f(t)= -cos 3t?

Answer:
option c
amplitude 1 ; period 2π/3
Step-by-step explanation:
Given in the question a function,
f(t)=-cos3t
Standard form of cosine function is
f(t)=acos(bt)
Amplitude is given by = |a|
Period of function is given by = 2π/b
So the amplitude is |-1| = 1
the period is 2π/3 = 2π/3
Answer:
c. The amplitude is 1.
The period is [tex]\frac{2\pi}{3}[/tex]
Step-by-step explanation:
The given cosine function is ;
[tex]f(t)=-\cos 3t[/tex]
This function is of the form;
[tex]f(t)=a\cos bt[/tex]
The amplitude is given by |a|
|-1|=1
The period of this function is given by;
[tex]T=\frac{2\pi}{|b|}[/tex]
[tex]T=\frac{2\pi}{|3|}=\frac{2\pi}{3}[/tex]
The amplitude is 1.
The period is [tex]\frac{2\pi}{3}[/tex]