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Two different linear functions are shown below with two points given from each function. Use slope-intercept form or point-slope form to find the equation of each.
Linear Function A
Points: (–5, –2), (–5, 7)
Linear Function B
Points: (7, –5), (–2, –5)

Function A has:


The equation of line A is:


Function B has:


The equation of line B is:

Respuesta :

gmany

Answer:

A: x = -5

B: y = -5

Step-by-step explanation:

Function A:

(-5, -2), (-5, 7) It's not a function, because for x = -5 we have two different values of y!

The graph is a vertical line x = -5

Function B:

(7, -5), (-2, -5) It's a function.

The graph is a horizontal line y = -5

MrRoyal

The slope-intercept form of a linear function is [tex]y = mx + c[/tex].

  • The equation of function A is: [tex]x = -5[/tex].
  • The equation of function B is: [tex]y = -5[/tex]

Linear function A

The points are given as: (-5, -2) and (-5,7)

First, we calculate the slope (m) of the line

[tex]m = \frac{y_2 - y_1}{x_2 - x_1}[/tex]

So, we have:

[tex]m = \frac{7--2}{-5--5}[/tex]

[tex]m = \frac{9}{0}[/tex]

[tex]m = und efine d[/tex]

The slope implies that, the point is a vertical line that passes through [tex]x = -5[/tex]

So, the equation is:

[tex]x = -5[/tex]

Linear function B

The points are given as: (7,-5) and (-2,-5)

First, we calculate the slope (m) of the line

[tex]m = \frac{y_2 - y_1}{x_2 - x_1}[/tex]

So, we have:

[tex]m = \frac{-5--5}{-2-7}[/tex]

[tex]m = \frac{0}{-9}[/tex]

[tex]m = 0[/tex]

The slope implies that, the point is a horizontal line that passes through [tex]y = -5[/tex]

So, the equation is:

[tex]y = -5[/tex]

See attachment for the graph of both functions.

Read more about linear functions at:

https://brainly.com/question/20286983

Ver imagen MrRoyal

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