Answer:
The total momentum before and after collision is 72000 kg-m/s.
Explanation:
Given that,
Mass of car = 1200 kg
Velocity of car = 10 m/s
Mass of truck = 2000 kg
Velocity of truck = 30 m/s
Using conservation of momentum
The total momentum before the collision is equal to the total momentum after collision.
[tex]m_{1}v_{1}+m_{2}v_{2}=(m_{1}+m_{2})V[/tex]
Where, [tex]m_{1}[/tex]=mass of car
[tex]v_{1}[/tex] =velocity of car
[tex]m_{1}[/tex]=mass of truck
[tex]v_{1}[/tex] =velocity of truck
Put the value into the formula
[tex]1200\times10+2000\times30=(1200+2000)V[/tex]
[tex]V=\dfrac{1200\times10+2000\times30}{(1200+2000)}[/tex]
[tex]V = 22.5\ m/s[/tex]
Now, The total momentum before collision is
[tex]P=m_{1}v_{1}+m_{2}v_{2}[/tex]
[tex]P=1200\times10+2000\times30[/tex]
[tex]P=72000\ kg-m/s[/tex]
The total momentum after collision is
[tex]P=(m_{1}+m_{2})v_{2}[/tex]
[tex]P=(1200+2000)\times22.5[/tex]
[tex]P= 72000 kg-m/s[/tex]
Hence, The total momentum before and after collision is 72000 kg-m/s.
