Answer:
32 cm
Explanation:
f = focal length of the converging lens = 16 cm
Since the lens produce the image with same size as object, magnification is given as
m = magnification = - 1
p = distance of the object from the lens
q = distance of the image from the lens
magnification is given as
m = - q/p
- 1 = - q/p
q = p eq-1
Using the lens equation, we get
1/p + 1/q = 1/f
using eq-1
1/p + 1/p = 1/16
p = 32 cm
The distance from the converging lens is 32 cm.
This is a type of lens which converges rays of light that are traveling parallel to its principal axis.
Parameters
f = focal length of the converging lens = 16 cm
Magnification = m = - q/p
where
m is magnification = - 1
p is distance of the object from the lens
q is distance of the image from the lens
m = - q/p
- 1 = - q/p
q = p
Lens equation : 1/p + 1/q = 1/f
Substitute q = p into equation
1/p + 1/p = 1/16
p = 32 cm
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