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3CuCl(aq) + 2Al(s) - AICI3(aq) + 3Cu(s)
How many grams of Cu will result from the complete reaction of
1.00 g Al in the reaction shown in the equation above?​

Respuesta :

MathPhys

Answer:

3.53 grams

Explanation:

First, convert mass of Al to moles:

1.00 g Al × (1 mol Al / 27.0 g Al) = 0.0370 mol Al

Then, use stoichiometry to find moles of Cu:

0.0370 mol Al × (3 mol Cu / 2 mol Al) = 0.0556 mol Cu

Finally, convert moles of Cu to mass:

0.0556 mol Cu × (63.5 g Cu / mol Cu) = 3.53 g Cu

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