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A rear wheel drive car of mass 1000 kg is accelerating with a constant acceleration without slipping from 0 to 60 m/s in 1 min. What will be friction force acting on each rear wheel of the car? 1000 N 60000 N 30000 N 500 N

Respuesta :

Answer:The force that acts on the wheels equals 1000 Newtons

Explanation:

We know acceleration is defined as

[tex]a=\frac{\Delta v}{\Delta t}=\frac{v_{2}-v_{1}}{t_{2}-t_{1}}\\\\\therefore a=\frac{60-0}{60-0}=1m/s^{2}[/tex]

Now using newton's second law we have

[tex]F_{ext}=m\times a\\\\\therefore F_{ext}=1000\times 1=1000N[/tex]

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