Answer:
B) more current.
Explanation:
When two lamps are connected in series then we have
[tex]R = R_1 + R_2[/tex]
now let the two lamps are identical
so we have
[tex]R_1 = R_2 = R[/tex]
now the total resistance of the lamps is given as
[tex]R_{eq} = R + R[/tex]
now the current in that case is given as
[tex]i = \frac{V}{R_{eq}}[/tex]
[tex]i = \frac{V}{2R}[/tex]
Now when lamps are connected in parallel
net resistance of two lamps is given as
[tex]\frac{1}{R_eq} = \frac{1}{R} + \frac{1}{R}[/tex]
so now we have
[tex]\frac{1}{R_{eq}} = \frac{2}{R}[/tex]
so we have
[tex]R_{eq} = \frac{R}{2}[/tex]
so now the current through the battery will be
[tex]i = \frac{V}{R/2} = \frac{2V}{R}[/tex]
So current will be more when two lamps are connected in parallel