Lisa opened a savings account and deposited $6000. The account earns %5 interest annually. She makes no further deposits and does not withdraw any money. In t years, she has $8865, in this account.

Respuesta :

Answer:

The time t is [tex]9.55\ years[/tex]

Step-by-step explanation:

we know that

The simple interest formula is equal to

[tex]A=P(1+rt)[/tex]

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest  

t is Number of Time Periods

in this problem we have

[tex]t=t\ years\\ P=\$6,000\\ A=\$8,865\\r=0.05[/tex]

substitute in the formula above  and solve for t

[tex]8,865=6,000(1+0.05t)[/tex]

[tex](8,865/6,000)=(1+0.05t)[/tex]

[tex]0.05t=(8,865/6,000)-1[/tex]

[tex]t=[(8,865/6,000)-1]/0.05[/tex]

[tex]t=9.55\ years[/tex]

Answer:

6000*(1.05)^t=8865

Step-by-step explanation: