Respuesta :
Answer:
a) 0.81 A
b) 0.33 A , 0.48 A
c) 10 Volts , 10 volts
Explanation:
[tex]R_{1}[/tex] = 30 Ω
[tex]R_{2}[/tex] = 21 Ω
[tex]V[/tex] = Voltage of the battery = 10 Volts
a)
Parallel combination of resistance is given as
[tex]R = \frac{R_{1}R_{2}}{R_{1} + R_{2}}[/tex]
[tex]R = \frac{(30) (21)}{30 + 21}[/tex]
[tex]R = 12.4[/tex] Ω
[tex]i[/tex] = Total current flowing through the circuit
Total current flowing through the circuit is given as
[tex]i = \frac{V}{R}[/tex]
[tex]i = \frac{10}{12.4}[/tex]
[tex]i = 0.81[/tex] A
b)
In parallel, Voltage remain same.
[tex]V_{1}[/tex] = Potential difference across R₁ = 10 Volts
[tex]V_{2}[/tex] = Potential difference across R₂ = 10 Volts
Current flowing through individual resistors is given as
[tex]i_{1} = \frac{V_{1}}{R_{1}}[/tex]
[tex]i_{1} = \frac{10}{30}[/tex]
[tex]i_{1} = 0.33[/tex] A
[tex]i_{2} = \frac{V_{2}}{R_{2}}[/tex]
[tex]i_{2} = \frac{10}{21}[/tex]
[tex]i_{2} = 0.48[/tex] A
c)
In parallel, Voltage remain same, hence
[tex]V_{1}[/tex] = [tex]V_{2}[/tex] = 10 Volts
