Answer:
[tex]\bold{Q17}\ \angle A\\\\\bold{Q18}\ R\\\\\bold{Q19}\ T\\\\\bold{Q20}\ \angle B\ \leftrightarrow\ \angle C[/tex]
Step-by-step explanation:
Q17
[tex]\overline{WA},\ \overline{AS}\ -\ A\ \text{is common}.\ \text{Therefore your answer is}\ \angle A\\\\\text{for}\ \overline{WS}\ \text{and}\ \overline{WA}\to\angle W\\\\\text{for}\ \overline{WS}\ \text{and}\ \overline{SA}\to\angle S\\\\============================[/tex]
For Q18 and Q19.
If ΔABC ≅ ΔSRT (congruent), then
[tex]A\ \leftrightarrow\ S\\ B\ \leftrightarrow\ R\\ C\ \leftrightarrow\ T\\\\============================[/tex]
Q20
[tex]\text{If}\ AB\cong AC,\ BD\cong CD,\ RSTU\ \text{is a parallelogram (rectangle)},\ \text{then}\\\\\angle 1\ \leftrightarrow\ \angle2\\\angle3\ \leftrightarrow\ \angle4\\\angle C\leftrightarrow\ \angle B\\\angle 5\ \leftrightarrow\ \angle6\\\angle7\ \leftrightarrow\ \angle 8\\\angle R\ \leftrightarrow\ \angle T\\\angle S\ \leftrightarrow\ \angle U[/tex]
