Answer:
The fraction of the time is 38.67%.
Explanation:
Given that,
Energy = 4.68 KJ
Resistance = 60
Voltage =110 V
If the rate of heat energy supplied by the coil to the oil bath = Q
[tex]Q=4.68\ kJ/min[/tex]
We need to calculate the power released by the resistor at voltage
[tex]P=\dfrac{V^2}{R}[/tex]
Put the value into the formula
[tex]P=\dfrac{110^2}{60}[/tex]
[tex]P=201.7\ W[/tex]
[tex]P=12.102\ KJ/min[/tex]
We need to calculate the fraction of the time
[tex]T=\dfrac{Q}{P}[/tex]
Put the value into the formula
[tex]T=\dfrac{4.68}{12.102}[/tex]
[tex]T=0.3867[/tex]
The percentage of time is
[tex]T = 38.67\%[/tex]
Hence, The fraction of the time is 38.67%.
