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At t = 0.0 s, a runner is moving forward (in the positive direction along the x-axis) at a
speed of 7.0 m/s. For 2.0 s the runner accelerates to his left at 0.50 m/s2

and backward

at 1.0 m/s2
. What is the runner’s position at t = 2.0 s in terms of the component
directions (forward/back and left/right)?

Respuesta :

Answer:

Way forward S_1 = 7\cdot2 - \frac{1\cdot2^{2}}{2} = 12 (m),S

1

=7⋅2−

2

1⋅2

2

=12(m),

path left S_2 = \frac{0.5\cdot2^{2}}{2} = 1 (m)S

2

=

2

0.5⋅2

2

=1(m) ,

therefore, the position of the runner is "forward and left."

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