Respuesta :
Answer:
The final volume must be 400 mL.
Explanation:
Let us assume the Initial volume as 100ml
Using dilution factor formula
[tex]\\$M_{1} \times V_{1}=M_{2} \times V_{2}$\\\\$0.400 M \times 100 m l=0.100 M \times V_{2}$[/tex]
So,
[tex]$V_{2}=\frac{0.400 M \times 100 m l}{0.100 M}=400 m l$[/tex]
Thus, the final volume must be 400 mL.
Explanation:
Molarity of HCl ,[tex]M_1= 0.400 M[/tex]
Volume of the HCl solution = [tex]V_1=500mL[/tex] (assume)
Molarity of HCl after dilution [tex]M_1= 0.100 M[/tex]
Volume of new HCl solution = [tex]V_2[/tex]
[tex]M_1V_1=M_2V_2[/tex]
[tex]0.400 M\times 500 mL=0.100 M\times V_2[/tex]
[tex]V_2=\frac{0.400 M\times 500 mL}{0.100 M}=2000 mL[/tex]
[tex]\frac{V_1}{V_2}=\frac{500 mL}{2000 mL}[/tex]
[tex]V_2=4\times V_1[/tex]
In order to dilute a HCl solution from 0.400 M to 0.100 M the final volume must be 4 times the initial volume of 0.400 M HCl solution .
