Answer:
a) x = 10
b) x = -40
c) x = 10, -40
Step-by-step explanation:
a)
[tex]x-10=0[/tex]
Taking 10 to the right hand side 10 becomes positive
[tex]\\\Rightarrow x=10[/tex]
So x = 10
b)
[tex]\frac{x}{2}+20=0[/tex]
Taking 20 to the right hand side 20 becomes negative
[tex]\frac{x}{2}=-20[/tex]
Multiplying both sides by 2
[tex]x=-40[/tex]
So, x = -40
c)
[tex](x-10)(\frac{x}{2}+20)=0\\\Rightarrow x-10=0, \frac{x}{2}+20=0\\\Rightarrow x=10, \frac{x}{2}=-20\\\Rightarrow x=10, x=-40[/tex]
Hence, x = 10, -40
So, two solutions can be provided
