Answer:
The value of x will be -11.5
Step-by-step explanation:
We have given point (x , -3 ) which is equidistant from (1, -2 ) and y =2
And we have to find the value f x
y =2 means the point (0, 2 )
So distance between the point (x ,-3 ) and ( 1 , -2 )
[tex]d=\sqrt{(x-1)^2+(-3-(-2))^2}=\sqrt{(x-1)^2+1}[/tex]
And distance between point (x ,-3 ) and ( 0 , 2 )
[tex]d=\sqrt{(x-0)^2+(-3-(2))^2}=\sqrt{x^2+25}[/tex]
As these distance are equal
So [tex]\sqrt{x^2+25}=\sqrt{(x-1)^2+1}[/tex]
Squaring both side
[tex]{x^2+25}=(x-1)^2+1[/tex]
x = -11.5
