contestada

For the material in the previous question that yields at 200 MPa, what is the maximum mass, in kg, that a cylindrical bar with diameter of 4.5 cm can support without yielding ? Recall that a mass of 1 kg has a weight of 9.81 N at sea-level. Answer Format: X (no decimal) Unit: kg Example: if you calculate 41321.78.... enter 41322

Respuesta :

Answer:

The maximum mass is 32458 kg.

Explanation:

Given that,

Diameter = 4.5 cm

Yield stress = 200 MPa

We need to calculate the mass

Using formula of stress

[tex]\sigma=\dfrac{F}{A}[/tex]

[tex]\sigma=\dfrac{mg}{\pi r^2}[/tex]

Where, m = mass

r = radius

Put the value into the formula

[tex]200\times10^{6}=\dfrac{m\times9.8}{\pi\times\dfrac{(4.5\times10^{-2})^2}{4}}[/tex]

[tex]m=\dfrac{200\times10^{6}\times\pi\times\dfrac{(4.5\times10^{-2})^2}{4}}{9.8}[/tex]

[tex]m=32458\ kg[/tex]

Hence, The maximum mass is 32458 kg.