Answer with Step-by-step explanation:
We are given that
[tex]f:Z+\rightarrow [/tex] (perfect squares)
Assign each term number to the square of that number.
It can be write as
[tex]f(x)=x^2[/tex] where [tex]x^2[/tex] is a perfect square number.
a.[/tex]f(3)=(3)^2=9[/tex]
It means that when we assign 3 then we get its corresponding perfect square number is 9.
b.[tex]f(x)=49[/tex]
49 is a perfect square number and 49 is square of 7.
Therefore, x=7
7 is that number when we substitute in given function then we get perfect square number 49.
c.-3 is not in the domain of f because the domain of sequence is always a set of natural.
d.50 is not in the range of f because is 50 is not a square of any number .Therefore, 50 is not a square number.Hence, 50 is not in the range of f.