Answer:
108.47N
Explanation:
Hello! To solve this problem, the first thing we must do is find the acceleration of the ball taking into account that part of the rest and that it is constant, the equation that defines this movement is as follows
[tex]\frac{Vf^{2}-Vo^2}{2.X} =a[/tex]
Vf=97mi/h=43.36m/s= final velocity
X=1.3m=Distance travelled
Vo=0m/S=initial velocity
a=acceleration
Solving
[tex]\frac{(43.36^{2}-0^2}{2.(1.3)} =723.11m/s^2[/tex]
finally we remember the second law of newton that states that the product of mass by acceleration is equal to force
F=ma
where
F=force
m=mass=0.15kg
a=aceleration
F=(0.15kg)(723.11m/S^2)=108.47N
The average force (in Newton) exerted on the baseball is 2.50 Newton.
Given the following data:
To determine the average force (in Newton) exerted on the ball:
First of all, we would determine the acceleration of the baseball by using the third equation of motion:
[tex]V^2 =U^2 +2aS\\\\43.36 = 0^2 + 2a(1.3)\\\\43.36 = 2.6a\\\\a=\frac{43.36}{2.6}[/tex]
Acceleration, a = 16.68 [tex]m/s^2[/tex]
For the average force:
From Newton's Second Law of Motion, average force is given by this formula:
[tex]Force = mass \times acceleration\\\\Force = 0.15 \times 16.68[/tex]
Force = 2.50 Newton.
Read more on force here: brainly.com/question/1121817
